
192.168.1.255 is the broadcast address of 192.168.1.0/24 network. /24 is the default cidr of class c. so by broadcasting this packet, it causes the increase in network traffic and overload. so the routers are designed to disregard this packet
Here we need to establish a default static root synatx of static route ip route prefix mask {ip-address interface-type interface-number [ip-address]} so the best option can be ip route 0.0.0.0 0.0.0.0 S 0/0/0
Different frames if found out from different encapsulation the host encapsulates the packet and sent to the switch. so this becomes first encapsulation now the switch forwards the same frame to router R1 nw this encapsulates the frame and sent to R2 this becomes the sencond encapsulation R2 receives this frame and again encapsulates it before forwarding to server 1 this becomes the third so 3 encapsulation implies in three different frames the packet is transelated form hots to server1
192.168.1.0-192.168.1.255 is the reserved private ip address so inorder to use internet with private address , address translation is required which can be done by configuring nat(network address translation)

192.168.1.250/24 is given as the routers ip address at fa 0/0.
/24 means the default cidr value,
and 192.x.x.x indicates a class c ip address.
so for class c default mask is given as 255.255.255.0
default mask class a 255.0.0.0
calss b 255.255.0.0
class c 255.255.255.0
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