Which two devices can interfere with the operation of a wireless network because they operate on similar frequencies? (Choose two.)


A:copier
B:microwave oven
C:toaster
D:cordless phone
E:IP phone
F:AM radio

uwave oven and cordless fone


Which encryption type does WPA 2 use ?

A: AES-CCMP
B: PPK via IV
C: PSK
D: TKIP/MIC


The encryption used by WPA 2 is AES-CCMP.
This make use of counter mode and CBC-MAC
cryptographic techniques to ensure security
between client and access point

DRAG N DROP

drag n drop

HOT SPOT 2

192.168.1.255 is the broadcast address of 192.168.1.0/24 network. /24 is the default cidr of class c. so by broadcasting this packet, it causes the increase in network traffic and overload. so the routers are designed to disregard this packet









Here we need to establish a default static root synatx of static route ip route prefix mask {ip-address interface-type interface-number [ip-address]} so the best option can be ip route 0.0.0.0 0.0.0.0 S 0/0/0









Different frames if found out from different encapsulation the host encapsulates the packet and sent to the switch. so this becomes first encapsulation now the switch forwards the same frame to router R1 nw this encapsulates the frame and sent to R2 this becomes the sencond encapsulation R2 receives this frame and again encapsulates it before forwarding to server 1 this becomes the third so 3 encapsulation implies in three different frames the packet is transelated form hots to server1










192.168.1.0-192.168.1.255 is the reserved private ip address so inorder to use internet with private address , address translation is required which can be done by configuring nat(network address translation)









192.168.1.250/24 is given as the routers ip address at fa 0/0.
/24 means the default cidr value,
and 192.x.x.x indicates a class c ip address.

so for class c default mask is given as 255.255.255.0

default mask class a 255.0.0.0
calss b 255.255.0.0
class c 255.255.255.0

HOT SPOT

The host address may not be 172.30.4.4 as its not listed in the router output

The host addres is 172.30.0.4
Now looking at the router o/p and looking for the corresponding dlci(layer2) addres we can find
that the dlci no is 702

From the topology it is seen that the S-AMER(.3) has the ip address 172.30.0.3 and from the o/p it is seen that the corresponding dlci is 196 nw follow the syntax of static frame relay mapping








The default encapsulation for cisco routers is HDLC. now looking at the router configuration,the interface serial1/1 has no encapsulation specified and tat router uses the default encapsulation...ie..mideeast branch







In a frame relay network , the passwords shud
match..from config its seen tat a password T1net
is set..so the appropriate password wil be telnet.

welcomin ur comments......